Base | Representation |
---|---|
bin | 11001000101101110… |
… | …01011110110001111 |
3 | 1021202201210102020101 |
4 | 30202313023312033 |
5 | 210041231344204 |
6 | 10104332231531 |
7 | 654536233336 |
oct | 144267136617 |
9 | 37681712211 |
10 | 13469793679 |
11 | 57923903a1 |
12 | 273b00b5a7 |
13 | 136880bc24 |
14 | 91acdad1d |
15 | 53c7eeea4 |
hex | 322dcbd8f |
13469793679 has 2 divisors, whose sum is σ = 13469793680. Its totient is φ = 13469793678.
The previous prime is 13469793641. The next prime is 13469793697. The reversal of 13469793679 is 97639796431.
Together with next prime (13469793697) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13469793679 - 213 = 13469785487 is a prime.
It is a super-3 number, since 3×134697936793 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13469793679.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13469793979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6734896839 + 6734896840.
It is an arithmetic number, because the mean of its divisors is an integer number (6734896840).
Almost surely, 213469793679 is an apocalyptic number.
13469793679 is a deficient number, since it is larger than the sum of its proper divisors (1).
13469793679 is an equidigital number, since it uses as much as digits as its factorization.
13469793679 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46294416, while the sum is 64.
The spelling of 13469793679 in words is "thirteen billion, four hundred sixty-nine million, seven hundred ninety-three thousand, six hundred seventy-nine".
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