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13470133332407 is a prime number
BaseRepresentation
bin1100010000000100001010…
…0000110010100110110111
31202200201202202022022211012
43010001002200302212313
53231143313113114112
644352032133302435
72560120314112313
oct304010240624667
952621682268735
1013470133332407
114323719111834
121616728494a1b
137692c72555cb
14347d5a7cab43
151855c822c022
hexc40428329b7

13470133332407 has 2 divisors, whose sum is σ = 13470133332408. Its totient is φ = 13470133332406.

The previous prime is 13470133332361. The next prime is 13470133332431. The reversal of 13470133332407 is 70423333107431.

It is a strong prime.

It is an emirp because it is prime and its reverse (70423333107431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13470133332407 - 26 = 13470133332343 is a prime.

It is a super-2 number, since 2×134701333324072 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13470133332307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6735066666203 + 6735066666204.

It is an arithmetic number, because the mean of its divisors is an integer number (6735066666204).

Almost surely, 213470133332407 is an apocalyptic number.

13470133332407 is a deficient number, since it is larger than the sum of its proper divisors (1).

13470133332407 is an equidigital number, since it uses as much as digits as its factorization.

13470133332407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 381024, while the sum is 41.

Adding to 13470133332407 its reverse (70423333107431), we get a palindrome (83893466439838).

The spelling of 13470133332407 in words is "thirteen trillion, four hundred seventy billion, one hundred thirty-three million, three hundred thirty-two thousand, four hundred seven".