13471103 has 2 divisors, whose sum is σ = 13471104. Its totient is φ = 13471102.

The previous prime is 13471097. The next prime is 13471121. The reversal of 13471103 is 30117431.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (30117431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13471103 - 2¹⁴ = 13454719 is a prime.

It is a super-3 number, since 3×13471103³ (a number of 22 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13471153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6735551 + 6735552.

It is an arithmetic number, because the mean of its divisors is an integer number (6735552).

Almost surely, 2^13471103 is an apocalyptic number.

13471103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13471103 is an equidigital number, since it uses as much as digits as its factorization.

13471103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

The square root of 13471103 is about 3670.3001239681. The cubic root of 13471103 is about 237.9401433637.

Adding to 13471103 its reverse (30117431), we get a palindrome (43588534).

The spelling of 13471103 in words is "thirteen million, four hundred seventy-one thousand, one hundred three".