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1347710420801 is a prime number
BaseRepresentation
bin10011100111001001110…
…011010000011101000001
311202211200020220221122102
4103213021303100131001
5134040102331431201
62511043555320145
7166240343364203
oct23471163203501
94684606827572
101347710420801
1147a619441528
121992415b0055
139a11c700274
144932dba0773
15250cc7a626b
hex139c9cd0741

1347710420801 has 2 divisors, whose sum is σ = 1347710420802. Its totient is φ = 1347710420800.

The previous prime is 1347710420789. The next prime is 1347710420803. The reversal of 1347710420801 is 1080240177431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1313132646400 + 34577774401 = 1145920^2 + 185951^2 .

It is a cyclic number.

It is not a de Polignac number, because 1347710420801 - 26 = 1347710420737 is a prime.

Together with 1347710420803, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1347710420803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 673855210400 + 673855210401.

It is an arithmetic number, because the mean of its divisors is an integer number (673855210401).

Almost surely, 21347710420801 is an apocalyptic number.

It is an amenable number.

1347710420801 is a deficient number, since it is larger than the sum of its proper divisors (1).

1347710420801 is an equidigital number, since it uses as much as digits as its factorization.

1347710420801 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 37632, while the sum is 38.

The spelling of 1347710420801 in words is "one trillion, three hundred forty-seven billion, seven hundred ten million, four hundred twenty thousand, eight hundred one".