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134811497 is a prime number
BaseRepresentation
bin10000000100100…
…00111101101001
3100101200010121102
420002100331221
5234002431442
621213251145
73224610302
oct1002207551
9311603542
10134811497
116a108967
1239193ab5
1321c11822
1413c937a9
15bc7e232
hex8090f69

134811497 has 2 divisors, whose sum is σ = 134811498. Its totient is φ = 134811496.

The previous prime is 134811491. The next prime is 134811499. The reversal of 134811497 is 794118431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107101801 + 27709696 = 10349^2 + 5264^2 .

It is a cyclic number.

It is not a de Polignac number, because 134811497 - 212 = 134807401 is a prime.

Together with 134811499, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134811497.

It is not a weakly prime, because it can be changed into another prime (134811491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67405748 + 67405749.

It is an arithmetic number, because the mean of its divisors is an integer number (67405749).

Almost surely, 2134811497 is an apocalyptic number.

It is an amenable number.

134811497 is a deficient number, since it is larger than the sum of its proper divisors (1).

134811497 is an equidigital number, since it uses as much as digits as its factorization.

134811497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24192, while the sum is 38.

The square root of 134811497 is about 11610.8353274000. The cubic root of 134811497 is about 512.7539056770.

The spelling of 134811497 in words is "one hundred thirty-four million, eight hundred eleven thousand, four hundred ninety-seven".