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13482447011431 is a prime number
BaseRepresentation
bin1100010000110010000001…
…1101101111111001100111
31202201220112220200000220021
43010030200131233321213
53231344022413331211
644401430050220011
72561034414500206
oct304144035577147
952656486600807
1013482447011431
114328967940072
121618ba4284607
1376a50a397208
143487a7d3d23d
15185a992ae771
hexc432076fe67

13482447011431 has 2 divisors, whose sum is σ = 13482447011432. Its totient is φ = 13482447011430.

The previous prime is 13482447011401. The next prime is 13482447011483. The reversal of 13482447011431 is 13411074428431.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13482447011431 - 29 = 13482447010919 is a prime.

It is a super-2 number, since 2×134824470114312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13482447011401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6741223505715 + 6741223505716.

It is an arithmetic number, because the mean of its divisors is an integer number (6741223505716).

Almost surely, 213482447011431 is an apocalyptic number.

13482447011431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13482447011431 is an equidigital number, since it uses as much as digits as its factorization.

13482447011431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 258048, while the sum is 43.

The spelling of 13482447011431 in words is "thirteen trillion, four hundred eighty-two billion, four hundred forty-seven million, eleven thousand, four hundred thirty-one".