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1348310149 is a prime number
BaseRepresentation
bin101000001011101…
…1001010010000101
310110222002020210221
41100113121102011
510230131411044
6341442544341
745261306244
oct12027312205
93428066727
101348310149
116320a440a
123176680b1
13186451174
14cb0d895b
157d584484
hex505d9485

1348310149 has 2 divisors, whose sum is σ = 1348310150. Its totient is φ = 1348310148.

The previous prime is 1348310141. The next prime is 1348310203. The reversal of 1348310149 is 9410138431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 749773924 + 598536225 = 27382^2 + 24465^2 .

It is a cyclic number.

It is not a de Polignac number, because 1348310149 - 23 = 1348310141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1348310141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674155074 + 674155075.

It is an arithmetic number, because the mean of its divisors is an integer number (674155075).

Almost surely, 21348310149 is an apocalyptic number.

It is an amenable number.

1348310149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1348310149 is an equidigital number, since it uses as much as digits as its factorization.

1348310149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 34.

The square root of 1348310149 is about 36719.3429815949. The cubic root of 1348310149 is about 1104.7481115420.

It can be divided in two parts, 13483 and 10149, that added together give a palindrome (23632).

The spelling of 1348310149 in words is "one billion, three hundred forty-eight million, three hundred ten thousand, one hundred forty-nine".