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134841154460561 is a prime number
BaseRepresentation
bin11110101010001100100111…
…000111001101101110010001
3122200102200120220012221100122
4132222030213013031232101
5120133214141020214221
61154441100551200025
740254644336516633
oct3652144707155621
9580380526187318
10134841154460561
1139a678a343396a
1213159151976015
135a3160a61aca3
1425424bd4a8a53
15108c7db86eeab
hex7aa3271cdb91

134841154460561 has 2 divisors, whose sum is σ = 134841154460562. Its totient is φ = 134841154460560.

The previous prime is 134841154460531. The next prime is 134841154460569. The reversal of 134841154460561 is 165064451148431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91633617777025 + 43207536683536 = 9572545^2 + 6573244^2 .

It is a cyclic number.

It is not a de Polignac number, because 134841154460561 - 26 = 134841154460497 is a prime.

It is not a weakly prime, because it can be changed into another prime (134841154460569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67420577230280 + 67420577230281.

It is an arithmetic number, because the mean of its divisors is an integer number (67420577230281).

Almost surely, 2134841154460561 is an apocalyptic number.

It is an amenable number.

134841154460561 is a deficient number, since it is larger than the sum of its proper divisors (1).

134841154460561 is an equidigital number, since it uses as much as digits as its factorization.

134841154460561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5529600, while the sum is 53.

The spelling of 134841154460561 in words is "one hundred thirty-four trillion, eight hundred forty-one billion, one hundred fifty-four million, four hundred sixty thousand, five hundred sixty-one".