Base | Representation |
---|---|
bin | 11110101011001101111111… |
… | …110000001010110010000011 |
3 | 122200200101210201100010120122 |
4 | 132223031333300022302003 |
5 | 120140341431413140123 |
6 | 1154533231302330455 |
7 | 40263011203034051 |
oct | 3653157760126203 |
9 | 580611721303518 |
10 | 134911361068163 |
11 | 39a94650211319 |
12 | 1316a885a29a2b |
13 | 5a381187c4354 |
14 | 2545a5d7031d1 |
15 | 108e54a192bc8 |
hex | 7ab37fc0ac83 |
134911361068163 has 2 divisors, whose sum is σ = 134911361068164. Its totient is φ = 134911361068162.
The previous prime is 134911361068151. The next prime is 134911361068241. The reversal of 134911361068163 is 361860163119431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134911361068163 - 210 = 134911361067139 is a prime.
It is not a weakly prime, because it can be changed into another prime (134911361068103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67455680534081 + 67455680534082.
It is an arithmetic number, because the mean of its divisors is an integer number (67455680534082).
Almost surely, 2134911361068163 is an apocalyptic number.
134911361068163 is a deficient number, since it is larger than the sum of its proper divisors (1).
134911361068163 is an equidigital number, since it uses as much as digits as its factorization.
134911361068163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1679616, while the sum is 53.
The spelling of 134911361068163 in words is "one hundred thirty-four trillion, nine hundred eleven billion, three hundred sixty-one million, sixty-eight thousand, one hundred sixty-three".
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