Base | Representation |
---|---|
bin | 10011101000101010101… |
… | …100111010110111011111 |
3 | 11202222212120000112010101 |
4 | 103220222230322313133 |
5 | 134101420023240341 |
6 | 2511513152321531 |
7 | 166325544013012 |
oct | 23505254726737 |
9 | 4688776015111 |
10 | 1349336149471 |
11 | 480283096542 |
12 | 199615b432a7 |
13 | 9a31b473aab |
14 | 49445a71379 |
15 | 25175388831 |
hex | 13a2ab3addf |
1349336149471 has 2 divisors, whose sum is σ = 1349336149472. Its totient is φ = 1349336149470.
The previous prime is 1349336149451. The next prime is 1349336149493. The reversal of 1349336149471 is 1749416339431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1349336149471 - 25 = 1349336149439 is a prime.
It is a super-3 number, since 3×13493361494713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1349336149411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674668074735 + 674668074736.
It is an arithmetic number, because the mean of its divisors is an integer number (674668074736).
Almost surely, 21349336149471 is an apocalyptic number.
1349336149471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349336149471 is an equidigital number, since it uses as much as digits as its factorization.
1349336149471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5878656, while the sum is 55.
The spelling of 1349336149471 in words is "one trillion, three hundred forty-nine billion, three hundred thirty-six million, one hundred forty-nine thousand, four hundred seventy-one".
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