Base | Representation |
---|---|
bin | 10011101000101010101… |
… | …100111010110111001011 |
3 | 11202222212120000112002122 |
4 | 103220222230322313023 |
5 | 134101420023240301 |
6 | 2511513152321455 |
7 | 166325544012653 |
oct | 23505254726713 |
9 | 4688776015078 |
10 | 1349336149451 |
11 | 480283096524 |
12 | 199615b4328b |
13 | 9a31b473a94 |
14 | 49445a71363 |
15 | 2517538881b |
hex | 13a2ab3adcb |
1349336149451 has 2 divisors, whose sum is σ = 1349336149452. Its totient is φ = 1349336149450.
The previous prime is 1349336149439. The next prime is 1349336149471. The reversal of 1349336149451 is 1549416339431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1349336149451 - 210 = 1349336148427 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1349336149393 and 1349336149402.
It is not a weakly prime, because it can be changed into another prime (1349336149411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674668074725 + 674668074726.
It is an arithmetic number, because the mean of its divisors is an integer number (674668074726).
Almost surely, 21349336149451 is an apocalyptic number.
1349336149451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349336149451 is an equidigital number, since it uses as much as digits as its factorization.
1349336149451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4199040, while the sum is 53.
The spelling of 1349336149451 in words is "one trillion, three hundred forty-nine billion, three hundred thirty-six million, one hundred forty-nine thousand, four hundred fifty-one".
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