1349340996050 has 12 divisors (see below), whose sum is σ = 2509774252746. Its totient is φ = 539736398400.

The previous prime is 1349340996013. The next prime is 1349340996079. The reversal of 1349340996050 is 506990439431.

It can be written as a sum of positive squares in 3 ways, for example, as 582197994361 + 767143001689 = 763019^2 + 875867^2 .

It is a super-2 number, since 2×1349340996050² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1349340995983 and 1349340996001.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13493409911 + ... + 13493410010.

Almost surely, 2^{1349340996050} is an apocalyptic number.

1349340996050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1349340996050 is a deficient number, since it is larger than the sum of its proper divisors (1160433256696).

1349340996050 is a wasteful number, since it uses less digits than its factorization.

1349340996050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26986819933 (or 26986819928 counting only the distinct ones).

The product of its (nonzero) digits is 3149280, while the sum is 53.

The spelling of 1349340996050 in words is "one trillion, three hundred forty-nine billion, three hundred forty million, nine hundred ninety-six thousand, fifty".