Base | Representation |
---|---|
bin | 11001001000101011… |
… | …11111110100000111 |
3 | 1021211110120011001102 |
4 | 30210111333310013 |
5 | 210114112214241 |
6 | 10111021050315 |
7 | 655260421202 |
oct | 144425776407 |
9 | 37743504042 |
10 | 13494648071 |
11 | 57a5416913 |
12 | 27473b699b |
13 | 1370a01a78 |
14 | 92032a939 |
15 | 53eaae39b |
hex | 32457fd07 |
13494648071 has 2 divisors, whose sum is σ = 13494648072. Its totient is φ = 13494648070.
The previous prime is 13494648049. The next prime is 13494648107. The reversal of 13494648071 is 17084649431.
Together with next prime (13494648107) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13494648071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13494648001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747324035 + 6747324036.
It is an arithmetic number, because the mean of its divisors is an integer number (6747324036).
Almost surely, 213494648071 is an apocalyptic number.
13494648071 is a deficient number, since it is larger than the sum of its proper divisors (1).
13494648071 is an equidigital number, since it uses as much as digits as its factorization.
13494648071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 47.
The spelling of 13494648071 in words is "thirteen billion, four hundred ninety-four million, six hundred forty-eight thousand, seventy-one".
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