Base | Representation |
---|---|
bin | 10011101000110111000… |
… | …100011011011010101100 |
3 | 11210000102000110001211122 |
4 | 103220313010123122230 |
5 | 134102331132414300 |
6 | 2511545523440112 |
7 | 166333643441615 |
oct | 23506704333254 |
9 | 4700360401748 |
10 | 1349543638700 |
11 | 48037a224244 |
12 | 199673526038 |
13 | 9a352450b9a |
14 | 49465442c0c |
15 | 251886c1c85 |
hex | 13a3711b6ac |
1349543638700 has 36 divisors (see below), whose sum is σ = 2955376781280. Its totient is φ = 534864997440.
The previous prime is 1349543638687. The next prime is 1349543638769. The reversal of 1349543638700 is 78363459431.
It is a super-2 number, since 2×13495436387002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 61894772 + ... + 61916571.
It is an arithmetic number, because the mean of its divisors is an integer number (82093799480).
Almost surely, 21349543638700 is an apocalyptic number.
1349543638700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1349543638700 is an abundant number, since it is smaller than the sum of its proper divisors (1605833142580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1349543638700 is a wasteful number, since it uses less digits than its factorization.
1349543638700 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123811466 (or 123811459 counting only the distinct ones).
The product of its (nonzero) digits is 6531840, while the sum is 53.
The spelling of 1349543638700 in words is "one trillion, three hundred forty-nine billion, five hundred forty-three million, six hundred thirty-eight thousand, seven hundred".
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