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1349964143197 is a prime number
BaseRepresentation
bin10011101001010000001…
…000100001101001011101
311210001111022200220120021
4103221100020201221131
5134104211310040242
62512055344352141
7166350240613345
oct23512010415135
94701438626507
101349964143197
1148057562451a
12199770315651
139a3bb5c1407
14494a5223d25
15251b0585b67
hex13a50221a5d

1349964143197 has 2 divisors, whose sum is σ = 1349964143198. Its totient is φ = 1349964143196.

The previous prime is 1349964143183. The next prime is 1349964143207. The reversal of 1349964143197 is 7913414699431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1252013296356 + 97950846841 = 1118934^2 + 312971^2 .

It is a cyclic number.

It is not a de Polignac number, because 1349964143197 - 231 = 1347816659549 is a prime.

It is a super-2 number, since 2×13499641431972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1349964149197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674982071598 + 674982071599.

It is an arithmetic number, because the mean of its divisors is an integer number (674982071599).

Almost surely, 21349964143197 is an apocalyptic number.

It is an amenable number.

1349964143197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1349964143197 is an equidigital number, since it uses as much as digits as its factorization.

1349964143197 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17635968, while the sum is 61.

The spelling of 1349964143197 in words is "one trillion, three hundred forty-nine billion, nine hundred sixty-four million, one hundred forty-three thousand, one hundred ninety-seven".