Search a number
-
+
13500211212017 is a prime number
BaseRepresentation
bin1100010001110100001101…
…0010110010111011110001
31202210121101221010220221022
43010131003102302323301
53232141413032241032
644413524510505225
72562233550633365
oct304350322627361
952717357126838
1013500211212017
114335453308982
121620521505215
1376c0ab7b78ca
143495b13092a5
15186288adb512
hexc47434b2ef1

13500211212017 has 2 divisors, whose sum is σ = 13500211212018. Its totient is φ = 13500211212016.

The previous prime is 13500211211957. The next prime is 13500211212031. The reversal of 13500211212017 is 71021211200531.

It is a happy number.

13500211212017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13420858575601 + 79352636416 = 3663449^2 + 281696^2 .

It is a cyclic number.

It is not a de Polignac number, because 13500211212017 - 28 = 13500211211761 is a prime.

It is a super-2 number, since 2×135002112120172 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13500211212517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750105606008 + 6750105606009.

It is an arithmetic number, because the mean of its divisors is an integer number (6750105606009).

Almost surely, 213500211212017 is an apocalyptic number.

It is an amenable number.

13500211212017 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500211212017 is an equidigital number, since it uses as much as digits as its factorization.

13500211212017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 26.

Adding to 13500211212017 its reverse (71021211200531), we get a palindrome (84521422412548).

The spelling of 13500211212017 in words is "thirteen trillion, five hundred billion, two hundred eleven million, two hundred twelve thousand, seventeen".