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13500211211957 is a prime number
BaseRepresentation
bin1100010001110100001101…
…0010110010111010110101
31202210121101221010220212002
43010131003102302322311
53232141413032240312
644413524510505045
72562233550633251
oct304350322627265
952717357126762
1013500211211957
114335453308928
121620521505185
1376c0ab7b7882
143495b1309261
15186288adb4c2
hexc47434b2eb5

13500211211957 has 2 divisors, whose sum is σ = 13500211211958. Its totient is φ = 13500211211956.

The previous prime is 13500211211909. The next prime is 13500211212017. The reversal of 13500211211957 is 75911211200531.

13500211211957 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11690887609636 + 1809323602321 = 3419194^2 + 1345111^2 .

It is a cyclic number.

It is not a de Polignac number, because 13500211211957 - 222 = 13500207017653 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13500211211957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13500211111957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750105605978 + 6750105605979.

It is an arithmetic number, because the mean of its divisors is an integer number (6750105605979).

Almost surely, 213500211211957 is an apocalyptic number.

It is an amenable number.

13500211211957 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500211211957 is an equidigital number, since it uses as much as digits as its factorization.

13500211211957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18900, while the sum is 38.

The spelling of 13500211211957 in words is "thirteen trillion, five hundred billion, two hundred eleven million, two hundred eleven thousand, nine hundred fifty-seven".