Base | Representation |
---|---|
bin | 1100010001110101011001… |
… | …1110110000011010101111 |
3 | 1202210122020100212021012002 |
4 | 3010131112132300122233 |
5 | 3232143042434131133 |
6 | 44414020450202515 |
7 | 2562244540024616 |
oct | 304352636603257 |
9 | 52718210767162 |
10 | 13500533114543 |
11 | 43355a8a92022 |
12 | 16205b128343b |
13 | 76c1303b3a87 |
14 | 349601d8087d |
15 | 1862a6ec4ce8 |
hex | c47567b06af |
13500533114543 has 2 divisors, whose sum is σ = 13500533114544. Its totient is φ = 13500533114542.
The previous prime is 13500533114533. The next prime is 13500533114561. The reversal of 13500533114543 is 34541133500531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13500533114543 - 24 = 13500533114527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13500533114497 and 13500533114506.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13500533114533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750266557271 + 6750266557272.
It is an arithmetic number, because the mean of its divisors is an integer number (6750266557272).
Almost surely, 213500533114543 is an apocalyptic number.
13500533114543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500533114543 is an equidigital number, since it uses as much as digits as its factorization.
13500533114543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 38.
The spelling of 13500533114543 in words is "thirteen trillion, five hundred billion, five hundred thirty-three million, one hundred fourteen thousand, five hundred forty-three".
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