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13501211341 is a prime number
BaseRepresentation
bin11001001001011110…
…00010001011001101
31021211220220121011111
430210233002023031
5210122302230331
610111413452021
7655400255122
oct144457021315
937756817144
1013501211341
1157a9099a02
122749641011
13137218c267
14921158749
15540458db1
hex324bc22cd

13501211341 has 2 divisors, whose sum is σ = 13501211342. Its totient is φ = 13501211340.

The previous prime is 13501211303. The next prime is 13501211401. The reversal of 13501211341 is 14311210531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13264359241 + 236852100 = 115171^2 + 15390^2 .

It is an emirp because it is prime and its reverse (14311210531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13501211341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13501211041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750605670 + 6750605671.

It is an arithmetic number, because the mean of its divisors is an integer number (6750605671).

Almost surely, 213501211341 is an apocalyptic number.

It is an amenable number.

13501211341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13501211341 is an equidigital number, since it uses as much as digits as its factorization.

13501211341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 22.

Adding to 13501211341 its reverse (14311210531), we get a palindrome (27812421872).

The spelling of 13501211341 in words is "thirteen billion, five hundred one million, two hundred eleven thousand, three hundred forty-one".