Base | Representation |
---|---|
bin | 10011101001100000001… |
… | …010101000010101001111 |
3 | 11210002012001211212112021 |
4 | 103221200022220111033 |
5 | 134110234140132234 |
6 | 2512142153551011 |
7 | 166360015145353 |
oct | 23514012502517 |
9 | 4702161755467 |
10 | 1350233130319 |
11 | 4806a3446527 |
12 | 199826415467 |
13 | 9a4322511a8 |
14 | 494ccc43463 |
15 | 251c8eba9b4 |
hex | 13a602a854f |
1350233130319 has 2 divisors, whose sum is σ = 1350233130320. Its totient is φ = 1350233130318.
The previous prime is 1350233130271. The next prime is 1350233130383. The reversal of 1350233130319 is 9130313320531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1350233130319 - 219 = 1350232606031 is a prime.
It is a super-2 number, since 2×13502331303192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1350233139319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675116565159 + 675116565160.
It is an arithmetic number, because the mean of its divisors is an integer number (675116565160).
Almost surely, 21350233130319 is an apocalyptic number.
1350233130319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350233130319 is an equidigital number, since it uses as much as digits as its factorization.
1350233130319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21870, while the sum is 34.
The spelling of 1350233130319 in words is "one trillion, three hundred fifty billion, two hundred thirty-three million, one hundred thirty thousand, three hundred nineteen".
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