Base | Representation |
---|---|
bin | 1100010001111100000111… |
… | …1010000110100010000101 |
3 | 1202210210212222021010221121 |
4 | 3010133001322012202011 |
5 | 3232210240333221000 |
6 | 44414515352313541 |
7 | 2562340313420002 |
oct | 304370172064205 |
9 | 52723788233847 |
10 | 13502335445125 |
11 | 433634339872a |
12 | 1620a149a28b1 |
13 | 76c35990b887 |
14 | 3497334a28a9 |
15 | 18636033db1a |
hex | c47c1e86885 |
13502335445125 has 32 divisors (see below), whose sum is σ = 17211016742400. Its totient is φ = 10571075668800.
The previous prime is 13502335445029. The next prime is 13502335445141. The reversal of 13502335445125 is 52154453320531.
It is not a de Polignac number, because 13502335445125 - 241 = 11303312189573 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 67974451 + ... + 68172799.
It is an arithmetic number, because the mean of its divisors is an integer number (537844273200).
Almost surely, 213502335445125 is an apocalyptic number.
It is an amenable number.
13502335445125 is a deficient number, since it is larger than the sum of its proper divisors (3708681297275).
13502335445125 is a wasteful number, since it uses less digits than its factorization.
13502335445125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 209998 (or 209988 counting only the distinct ones).
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 13502335445125 its reverse (52154453320531), we get a palindrome (65656788765656).
The spelling of 13502335445125 in words is "thirteen trillion, five hundred two billion, three hundred thirty-five million, four hundred forty-five thousand, one hundred twenty-five".
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