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135030402153407 is a prime number
BaseRepresentation
bin11110101100111100110111…
…001001110111101110111111
3122201002210001220010211022202
4132230330313021313232333
5120144314230422402112
61155104035502102115
740304424146413445
oct3654746711675677
9581083056124282
10135030402153407
113a030087864602
121318996857a93b
135a4640a128027
14254b713554b95
1510926b5d806c2
hex7acf37277bbf

135030402153407 has 2 divisors, whose sum is σ = 135030402153408. Its totient is φ = 135030402153406.

The previous prime is 135030402153323. The next prime is 135030402153461. The reversal of 135030402153407 is 704351204030531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135030402153407 - 222 = 135030397959103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135030402153007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67515201076703 + 67515201076704.

It is an arithmetic number, because the mean of its divisors is an integer number (67515201076704).

Almost surely, 2135030402153407 is an apocalyptic number.

135030402153407 is a deficient number, since it is larger than the sum of its proper divisors (1).

135030402153407 is an equidigital number, since it uses as much as digits as its factorization.

135030402153407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 38.

Adding to 135030402153407 its reverse (704351204030531), we get a palindrome (839381606183938).

The spelling of 135030402153407 in words is "one hundred thirty-five trillion, thirty billion, four hundred two million, one hundred fifty-three thousand, four hundred seven".