Base | Representation |
---|---|
bin | 1100010001111110110000… |
… | …0011011101011101101111 |
3 | 1202210212201020210100201101 |
4 | 3010133230003131131233 |
5 | 3232213212342311143 |
6 | 44415113452023531 |
7 | 2562363660555151 |
oct | 304375403353557 |
9 | 52725636710641 |
10 | 13503042541423 |
11 | 4336676544636 |
12 | 1620b91761ba7 |
13 | 76c440263c56 |
14 | 34979d366ad1 |
15 | 1863a2463b4d |
hex | c47ec0dd76f |
13503042541423 has 2 divisors, whose sum is σ = 13503042541424. Its totient is φ = 13503042541422.
The previous prime is 13503042541421. The next prime is 13503042541433. The reversal of 13503042541423 is 32414524030531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13503042541423 - 21 = 13503042541421 is a prime.
Together with 13503042541421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13503042541421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751521270711 + 6751521270712.
It is an arithmetic number, because the mean of its divisors is an integer number (6751521270712).
Almost surely, 213503042541423 is an apocalyptic number.
13503042541423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13503042541423 is an equidigital number, since it uses as much as digits as its factorization.
13503042541423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 13503042541423 its reverse (32414524030531), we get a palindrome (45917566571954).
The spelling of 13503042541423 in words is "thirteen trillion, five hundred three billion, forty-two million, five hundred forty-one thousand, four hundred twenty-three".
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