Base | Representation |
---|---|
bin | 11001001001101111… |
… | …00010100010010000 |
3 | 1021212002002212201221 |
4 | 30210313202202100 |
5 | 210123340103130 |
6 | 10111533334424 |
7 | 655425232525 |
oct | 144467424220 |
9 | 37762085657 |
10 | 13503441040 |
11 | 57aa382131 |
12 | 274a337414 |
13 | 13727900cb |
14 | 92157914c |
15 | 54074987a |
hex | 324de2890 |
13503441040 has 40 divisors (see below), whose sum is σ = 31400490240. Its totient is φ = 5400518016.
The previous prime is 13503441023. The next prime is 13503441041. The reversal of 13503441040 is 4014430531.
It is a tau number, because it is divible by the number of its divisors (40).
It is a junction number, because it is equal to n+sod(n) for n = 13503440996 and 13503441014.
It is not an unprimeable number, because it can be changed into a prime (13503441041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 797947 + ... + 814693.
It is an arithmetic number, because the mean of its divisors is an integer number (785012256).
Almost surely, 213503441040 is an apocalyptic number.
13503441040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13503441040 is an abundant number, since it is smaller than the sum of its proper divisors (17897049200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13503441040 is a wasteful number, since it uses less digits than its factorization.
13503441040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26839 (or 26833 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 13503441040 its reverse (4014430531), we get a palindrome (17517871571).
The spelling of 13503441040 in words is "thirteen billion, five hundred three million, four hundred forty-one thousand, forty".
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