Base | Representation |
---|---|
bin | 10011101001101011101… |
… | …011010011000001000111 |
3 | 11210002200112020000112002 |
4 | 103221223223103001013 |
5 | 134111133104240033 |
6 | 2512213253015515 |
7 | 166364551446455 |
oct | 23515353230107 |
9 | 4702615200462 |
10 | 1350426243143 |
11 | 480792454aaa |
12 | 19987b02459b |
13 | 9a463266733 |
14 | 4950a7519d5 |
15 | 251dae143e8 |
hex | 13a6bad3047 |
1350426243143 has 2 divisors, whose sum is σ = 1350426243144. Its totient is φ = 1350426243142.
The previous prime is 1350426243137. The next prime is 1350426243169. The reversal of 1350426243143 is 3413426240531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1350426243143 - 232 = 1346131275847 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350426243097 and 1350426243106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1350426243743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675213121571 + 675213121572.
It is an arithmetic number, because the mean of its divisors is an integer number (675213121572).
Almost surely, 21350426243143 is an apocalyptic number.
1350426243143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350426243143 is an equidigital number, since it uses as much as digits as its factorization.
1350426243143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 38.
The spelling of 1350426243143 in words is "one trillion, three hundred fifty billion, four hundred twenty-six million, two hundred forty-three thousand, one hundred forty-three".
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