Base | Representation |
---|---|
bin | 10011101001110011001… |
… | …101100001101010011011 |
3 | 11210010000100002111002201 |
4 | 103221303031201222123 |
5 | 134111412440002124 |
6 | 2512234010311031 |
7 | 166400645111602 |
oct | 23516315415233 |
9 | 4703010074081 |
10 | 1350552656539 |
11 | 480847847289 |
12 | 1998b5428477 |
13 | 9a4834c7868 |
14 | 4951d45aa39 |
15 | 251e7085144 |
hex | 13a73361a9b |
1350552656539 has 2 divisors, whose sum is σ = 1350552656540. Its totient is φ = 1350552656538.
The previous prime is 1350552656507. The next prime is 1350552656543. The reversal of 1350552656539 is 9356562550531.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350552656539 - 25 = 1350552656507 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1350552656539.
It is not a weakly prime, because it can be changed into another prime (1350552656239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675276328269 + 675276328270.
It is an arithmetic number, because the mean of its divisors is an integer number (675276328270).
Almost surely, 21350552656539 is an apocalyptic number.
1350552656539 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350552656539 is an equidigital number, since it uses as much as digits as its factorization.
1350552656539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18225000, while the sum is 55.
The spelling of 1350552656539 in words is "one trillion, three hundred fifty billion, five hundred fifty-two million, six hundred fifty-six thousand, five hundred thirty-nine".
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