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1350552656543 is a prime number
BaseRepresentation
bin10011101001110011001…
…101100001101010011111
311210010000100002111002212
4103221303031201222133
5134111412440002133
62512234010311035
7166400645111606
oct23516315415237
94703010074085
101350552656543
11480847847292
121998b542847b
139a4834c786c
144951d45aa3d
15251e7085148
hex13a73361a9f

1350552656543 has 2 divisors, whose sum is σ = 1350552656544. Its totient is φ = 1350552656542.

The previous prime is 1350552656539. The next prime is 1350552656591. The reversal of 1350552656543 is 3456562550531.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1350552656543 - 22 = 1350552656539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1350552656491 and 1350552656500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350557656543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675276328271 + 675276328272.

It is an arithmetic number, because the mean of its divisors is an integer number (675276328272).

Almost surely, 21350552656543 is an apocalyptic number.

1350552656543 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350552656543 is an equidigital number, since it uses as much as digits as its factorization.

1350552656543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100000, while the sum is 50.

The spelling of 1350552656543 in words is "one trillion, three hundred fifty billion, five hundred fifty-two million, six hundred fifty-six thousand, five hundred forty-three".