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135069581 is a prime number
BaseRepresentation
bin10000000110011…
…11111110001101
3100102011020122002
420003033332031
5234034211311
621223002045
73230033603
oct1003177615
9312136562
10135069581
116a274859
1239299325
1321ca213a
1413d1d873
15bcd093b
hex80cff8d

135069581 has 2 divisors, whose sum is σ = 135069582. Its totient is φ = 135069580.

The previous prime is 135069563. The next prime is 135069611. The reversal of 135069581 is 185960531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132940900 + 2128681 = 11530^2 + 1459^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135069581 is a prime.

It is a super-2 number, since 2×1350695812 = 36487583423031122, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135069541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67534790 + 67534791.

It is an arithmetic number, because the mean of its divisors is an integer number (67534791).

Almost surely, 2135069581 is an apocalyptic number.

It is an amenable number.

135069581 is a deficient number, since it is larger than the sum of its proper divisors (1).

135069581 is an equidigital number, since it uses as much as digits as its factorization.

135069581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 38.

The square root of 135069581 is about 11621.9439423876. The cubic root of 135069581 is about 513.0809035590.

The spelling of 135069581 in words is "one hundred thirty-five million, sixty-nine thousand, five hundred eighty-one".