Base | Representation |
---|---|
bin | 10011101010000000000… |
… | …110111011100011011011 |
3 | 11210010120102020110120222 |
4 | 103222000012323203123 |
5 | 134112333333001022 |
6 | 2512311300110255 |
7 | 166406213216216 |
oct | 23520006734333 |
9 | 4703512213528 |
10 | 1350769031387 |
11 | 4809489a3976 |
12 | 19995599538b |
13 | 9a4b9296209 |
14 | 495400a277d |
15 | 2520b076242 |
hex | 13a801bb8db |
1350769031387 has 2 divisors, whose sum is σ = 1350769031388. Its totient is φ = 1350769031386.
The previous prime is 1350769031377. The next prime is 1350769031389. The reversal of 1350769031387 is 7831309670531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350769031387 - 216 = 1350768965851 is a prime.
It is a super-2 number, since 2×13507690313872 (a number of 25 digits) contains 22 as substring.
Together with 1350769031389, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1350769031389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675384515693 + 675384515694.
It is an arithmetic number, because the mean of its divisors is an integer number (675384515694).
Almost surely, 21350769031387 is an apocalyptic number.
1350769031387 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350769031387 is an equidigital number, since it uses as much as digits as its factorization.
1350769031387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2857680, while the sum is 53.
The spelling of 1350769031387 in words is "one trillion, three hundred fifty billion, seven hundred sixty-nine million, thirty-one thousand, three hundred eighty-seven".
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