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135102483877 is a prime number
BaseRepresentation
bin111110111010010111…
…1000100110110100101
3110220201112011021122011
41331310233010312211
54203142213441002
6142022031034221
712521652110434
oct1756457046645
9426645137564
10135102483877
1152329914859
122222566b971
13c98103666a
14677900711b
1537aacb08d7
hex1f74bc4da5

135102483877 has 2 divisors, whose sum is σ = 135102483878. Its totient is φ = 135102483876.

The previous prime is 135102483863. The next prime is 135102483883. The reversal of 135102483877 is 778384201531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84026935876 + 51075548001 = 289874^2 + 225999^2 .

It is an emirp because it is prime and its reverse (778384201531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135102483877 - 215 = 135102451109 is a prime.

It is a super-2 number, since 2×1351024838772 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 135102483877.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135102484877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67551241938 + 67551241939.

It is an arithmetic number, because the mean of its divisors is an integer number (67551241939).

Almost surely, 2135102483877 is an apocalyptic number.

It is an amenable number.

135102483877 is a deficient number, since it is larger than the sum of its proper divisors (1).

135102483877 is an equidigital number, since it uses as much as digits as its factorization.

135102483877 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1128960, while the sum is 49.

The spelling of 135102483877 in words is "one hundred thirty-five billion, one hundred two million, four hundred eighty-three thousand, eight hundred seventy-seven".