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1351035555941 is a prime number
BaseRepresentation
bin10011101010001111111…
…111101001000001100101
311210011020222202022112202
4103222033333221001211
5134113410100242231
62512353540424245
7166415630513561
oct23521777510145
94704228668482
101351035555941
11480a753937a5
12199a0b0a8085
139a52c573156
14495676406a1
15252246715cb
hex13a8ffe9065

1351035555941 has 2 divisors, whose sum is σ = 1351035555942. Its totient is φ = 1351035555940.

The previous prime is 1351035555931. The next prime is 1351035555979. The reversal of 1351035555941 is 1495555301531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1205283405316 + 145752150625 = 1097854^2 + 381775^2 .

It is an emirp because it is prime and its reverse (1495555301531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1351035555941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351035555901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675517777970 + 675517777971.

It is an arithmetic number, because the mean of its divisors is an integer number (675517777971).

Almost surely, 21351035555941 is an apocalyptic number.

It is an amenable number.

1351035555941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351035555941 is an equidigital number, since it uses as much as digits as its factorization.

1351035555941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1012500, while the sum is 47.

The spelling of 1351035555941 in words is "one trillion, three hundred fifty-one billion, thirty-five million, five hundred fifty-five thousand, nine hundred forty-one".