1351035771401 has 2 divisors, whose sum is σ = 1351035771402. Its totient is φ = 1351035771400.

The previous prime is 1351035771389. The next prime is 1351035771403. The reversal of 1351035771401 is 1041775301531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1342029571600 + 9006199801 = 1158460^2 + 94901^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351035771401 - 2²² = 1351031577097 is a prime.

Together with 1351035771403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1351035771403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675517885700 + 675517885701.

It is an arithmetic number, because the mean of its divisors is an integer number (675517885701).

Almost surely, 2^{1351035771401} is an apocalyptic number.

It is an amenable number.

1351035771401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351035771401 is an equidigital number, since it uses as much as digits as its factorization.

1351035771401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 44100, while the sum is 38.

The spelling of 1351035771401 in words is "one trillion, three hundred fifty-one billion, thirty-five million, seven hundred seventy-one thousand, four hundred one".