Base | Representation |
---|---|
bin | 10011101010010000010… |
… | …111010010101000111111 |
3 | 11210011021102102022000212 |
4 | 103222100113102220333 |
5 | 134113413142140321 |
6 | 2512354321343035 |
7 | 166416034304654 |
oct | 23522027225077 |
9 | 4704242368025 |
10 | 1351041755711 |
11 | 480a7893877a |
12 | 199a11197a7b |
13 | 9a53093405b |
14 | 495683b5c2b |
15 | 25224e9855b |
hex | 13a905d2a3f |
1351041755711 has 2 divisors, whose sum is σ = 1351041755712. Its totient is φ = 1351041755710.
The previous prime is 1351041755699. The next prime is 1351041755719. The reversal of 1351041755711 is 1175571401531.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1351041755711 - 218 = 1351041493567 is a prime.
It is a super-2 number, since 2×13510417557112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351041755719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675520877855 + 675520877856.
It is an arithmetic number, because the mean of its divisors is an integer number (675520877856).
Almost surely, 21351041755711 is an apocalyptic number.
1351041755711 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351041755711 is an equidigital number, since it uses as much as digits as its factorization.
1351041755711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 73500, while the sum is 41.
The spelling of 1351041755711 in words is "one trillion, three hundred fifty-one billion, forty-one million, seven hundred fifty-five thousand, seven hundred eleven".
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