Base | Representation |
---|---|
bin | 10011101010010011111… |
… | …010000111011011001111 |
3 | 11210011102120022012211221 |
4 | 103222103322013123033 |
5 | 134114023402411323 |
6 | 2512404244024211 |
7 | 166420355564635 |
oct | 23522372073317 |
9 | 4704376265757 |
10 | 1351101216463 |
11 | 480aa9460499 |
12 | 199a29092067 |
13 | 9a54005272b |
14 | 49572253355 |
15 | 2522a2e155d |
hex | 13a93e876cf |
1351101216463 has 2 divisors, whose sum is σ = 1351101216464. Its totient is φ = 1351101216462.
The previous prime is 1351101216401. The next prime is 1351101216469. The reversal of 1351101216463 is 3646121011531.
It is a strong prime.
It is an emirp because it is prime and its reverse (3646121011531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1351101216463 - 217 = 1351101085391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351101216469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675550608231 + 675550608232.
It is an arithmetic number, because the mean of its divisors is an integer number (675550608232).
Almost surely, 21351101216463 is an apocalyptic number.
1351101216463 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351101216463 is an equidigital number, since it uses as much as digits as its factorization.
1351101216463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 34.
Adding to 1351101216463 its reverse (3646121011531), we get a palindrome (4997222227994).
The spelling of 1351101216463 in words is "one trillion, three hundred fifty-one billion, one hundred one million, two hundred sixteen thousand, four hundred sixty-three".
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