Base | Representation |
---|---|
bin | 10011101010010100000… |
… | …011100000001100011011 |
3 | 11210011102201221020100202 |
4 | 103222110003200030123 |
5 | 134114030020132321 |
6 | 2512404412452415 |
7 | 166420415524061 |
oct | 23522403401433 |
9 | 4704381836322 |
10 | 1351103677211 |
11 | 480aaa891272 |
12 | 199a29a7a10b |
13 | 9a5407047b2 |
14 | 495726d4031 |
15 | 2522a62a70b |
hex | 13a940e031b |
1351103677211 has 2 divisors, whose sum is σ = 1351103677212. Its totient is φ = 1351103677210.
The previous prime is 1351103677171. The next prime is 1351103677213. The reversal of 1351103677211 is 1127763011531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1351103677211 is a prime.
It is a super-2 number, since 2×13511036772112 (a number of 25 digits) contains 22 as substring.
Together with 1351103677213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1351103677213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675551838605 + 675551838606.
It is an arithmetic number, because the mean of its divisors is an integer number (675551838606).
Almost surely, 21351103677211 is an apocalyptic number.
1351103677211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351103677211 is an equidigital number, since it uses as much as digits as its factorization.
1351103677211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26460, while the sum is 38.
Adding to 1351103677211 its reverse (1127763011531), we get a palindrome (2478866688742).
The spelling of 1351103677211 in words is "one trillion, three hundred fifty-one billion, one hundred three million, six hundred seventy-seven thousand, two hundred eleven".
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