Base | Representation |
---|---|
bin | 10000000110110… |
… | …10010111001100 |
3 | 100102020102000100 |
4 | 20003122113030 |
5 | 234042042030 |
6 | 21223531100 |
7 | 3230301642 |
oct | 1003322714 |
9 | 312212010 |
10 | 135112140 |
11 | 6a2a3829 |
12 | 392b9a90 |
13 | 21cb8617 |
14 | 13d31192 |
15 | bcdd360 |
hex | 80da5cc |
135112140 has 72 divisors (see below), whose sum is σ = 412907040. Its totient is φ = 35760384.
The previous prime is 135112139. The next prime is 135112147. The reversal of 135112140 is 41211531.
135112140 is a `hidden beast` number, since 13 + 511 + 2 + 140 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (135112147) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 21921 + ... + 27399.
It is an arithmetic number, because the mean of its divisors is an integer number (5734820).
Almost surely, 2135112140 is an apocalyptic number.
135112140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 135112140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (206453520).
135112140 is an abundant number, since it is smaller than the sum of its proper divisors (277794900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135112140 is a wasteful number, since it uses less digits than its factorization.
135112140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5631 (or 5626 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
The square root of 135112140 is about 11623.7747741429. The cubic root of 135112140 is about 513.1347866933.
Adding to 135112140 its reverse (41211531), we get a palindrome (176323671).
It can be divided in two parts, 13511 and 2140, that added together give a palindrome (15651).
The spelling of 135112140 in words is "one hundred thirty-five million, one hundred twelve thousand, one hundred forty".
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