Base | Representation |
---|---|
bin | 111110111010101100… |
… | …1111110101010000011 |
3 | 110220202022022200100211 |
4 | 1331311121332222003 |
5 | 4203203103340231 |
6 | 142023112054551 |
7 | 12522146522122 |
oct | 1756531765203 |
9 | 426668280324 |
10 | 135113730691 |
11 | 523351a6745 |
12 | 22229394457 |
13 | c983473894 |
14 | 677a6d3ab9 |
15 | 37abc82eb1 |
hex | 1f7567ea83 |
135113730691 has 2 divisors, whose sum is σ = 135113730692. Its totient is φ = 135113730690.
The previous prime is 135113730673. The next prime is 135113730709. The reversal of 135113730691 is 196037311531.
It is a balanced prime because it is at equal distance from previous prime (135113730673) and next prime (135113730709).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135113730691 is a prime.
It is not a weakly prime, because it can be changed into another prime (135113700691) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67556865345 + 67556865346.
It is an arithmetic number, because the mean of its divisors is an integer number (67556865346).
Almost surely, 2135113730691 is an apocalyptic number.
135113730691 is a deficient number, since it is larger than the sum of its proper divisors (1).
135113730691 is an equidigital number, since it uses as much as digits as its factorization.
135113730691 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51030, while the sum is 40.
The spelling of 135113730691 in words is "one hundred thirty-five billion, one hundred thirteen million, seven hundred thirty thousand, six hundred ninety-one".
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