Base | Representation |
---|---|
bin | 111110111010101111… |
… | …0111100011011101101 |
3 | 110220202101202210211121 |
4 | 1331311132330123231 |
5 | 4203203422013201 |
6 | 142023200020541 |
7 | 12522163552654 |
oct | 1756536743355 |
9 | 426671683747 |
10 | 135115032301 |
11 | 52335a05657 |
12 | 22229901751 |
13 | c98380b172 |
14 | 677a95219b |
15 | 37abe3d9a1 |
hex | 1f757bc6ed |
135115032301 has 2 divisors, whose sum is σ = 135115032302. Its totient is φ = 135115032300.
The previous prime is 135115032293. The next prime is 135115032307. The reversal of 135115032301 is 103230511531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100472516676 + 34642515625 = 316974^2 + 186125^2 .
It is a cyclic number.
It is not a de Polignac number, because 135115032301 - 23 = 135115032293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135115032307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67557516150 + 67557516151.
It is an arithmetic number, because the mean of its divisors is an integer number (67557516151).
Almost surely, 2135115032301 is an apocalyptic number.
It is an amenable number.
135115032301 is a deficient number, since it is larger than the sum of its proper divisors (1).
135115032301 is an equidigital number, since it uses as much as digits as its factorization.
135115032301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 135115032301 its reverse (103230511531), we get a palindrome (238345543832).
The spelling of 135115032301 in words is "one hundred thirty-five billion, one hundred fifteen million, thirty-two thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •