Base | Representation |
---|---|
bin | 11110101110001100000001… |
… | …100100001110111011011110 |
3 | 122201101220110201011210120210 |
4 | 132232030001210032323132 |
5 | 120202212321011043124 |
6 | 1155211054201153250 |
7 | 40313523426056334 |
oct | 3656140144167336 |
9 | 581356421153523 |
10 | 135115402440414 |
11 | 3a063136254290 |
12 | 131a232aa8b826 |
13 | 5a5143518c246 |
14 | 2551898427b54 |
15 | 10949dd310a29 |
hex | 7ae30190eede |
135115402440414 has 64 divisors (see below), whose sum is σ = 295228032768000. Its totient is φ = 40884263178240.
The previous prime is 135115402440407. The next prime is 135115402440427. The reversal of 135115402440414 is 414044204511531.
It is a super-3 number, since 3×1351154024404143 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 159545907 + ... + 160390545.
It is an arithmetic number, because the mean of its divisors is an integer number (4612938012000).
Almost surely, 2135115402440414 is an apocalyptic number.
135115402440414 is an abundant number, since it is smaller than the sum of its proper divisors (160112630327586).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135115402440414 is a wasteful number, since it uses less digits than its factorization.
135115402440414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 848193.
The product of its (nonzero) digits is 153600, while the sum is 39.
Adding to 135115402440414 its reverse (414044204511531), we get a palindrome (549159606951945).
The spelling of 135115402440414 in words is "one hundred thirty-five trillion, one hundred fifteen billion, four hundred two million, four hundred forty thousand, four hundred fourteen".
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