Base | Representation |
---|---|
bin | 11001001010110000… |
… | …11000010101111111 |
3 | 1021212200022021002001 |
4 | 30211120120111333 |
5 | 210133041100142 |
6 | 10112442043131 |
7 | 655561346626 |
oct | 144530302577 |
9 | 37780267061 |
10 | 13512050047 |
11 | 5804222211 |
12 | 27511a94a7 |
13 | 13744b57b2 |
14 | 92277a6bd |
15 | 54139a5b7 |
hex | 32561857f |
13512050047 has 2 divisors, whose sum is σ = 13512050048. Its totient is φ = 13512050046.
The previous prime is 13512050039. The next prime is 13512050087. The reversal of 13512050047 is 74005021531.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13512050047 - 23 = 13512050039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13512049997 and 13512050024.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13512050087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756025023 + 6756025024.
It is an arithmetic number, because the mean of its divisors is an integer number (6756025024).
Almost surely, 213512050047 is an apocalyptic number.
13512050047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13512050047 is an equidigital number, since it uses as much as digits as its factorization.
13512050047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 28.
Adding to 13512050047 its reverse (74005021531), we get a palindrome (87517071578).
The spelling of 13512050047 in words is "thirteen billion, five hundred twelve million, fifty thousand, forty-seven".
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