Base | Representation |
---|---|
bin | 11110101110010000111011… |
… | …110101101101001101101011 |
3 | 122201102102002011112222010222 |
4 | 132232100323311231031223 |
5 | 120202304120304113411 |
6 | 1155213325312000255 |
7 | 40314101201463614 |
oct | 3656207365551553 |
9 | 581372064488128 |
10 | 135120675066731 |
11 | 3a0653a15394a2 |
12 | 131a336083008b |
13 | 5a51a95653183 |
14 | 2551c387b4c0b |
15 | 1094beb16a4db |
hex | 7ae43bd6d36b |
135120675066731 has 2 divisors, whose sum is σ = 135120675066732. Its totient is φ = 135120675066730.
The previous prime is 135120675066649. The next prime is 135120675066733. The reversal of 135120675066731 is 137660576021531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135120675066731 is a prime.
It is a super-2 number, since 2×1351206750667312 (a number of 29 digits) contains 22 as substring.
Together with 135120675066733, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (135120675066733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67560337533365 + 67560337533366.
It is an arithmetic number, because the mean of its divisors is an integer number (67560337533366).
Almost surely, 2135120675066731 is an apocalyptic number.
135120675066731 is a deficient number, since it is larger than the sum of its proper divisors (1).
135120675066731 is an equidigital number, since it uses as much as digits as its factorization.
135120675066731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4762800, while the sum is 53.
The spelling of 135120675066731 in words is "one hundred thirty-five trillion, one hundred twenty billion, six hundred seventy-five million, sixty-six thousand, seven hundred thirty-one".
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