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1351245121153 is a prime number
BaseRepresentation
bin10011101010011100011…
…111000100011010000001
311210011210121002022222021
4103222130133010122001
5134114322222334103
62512430424241441
7166424054010064
oct23523437043201
94704717068867
101351245121153
1148107270a194
12199a69310281
139a563ac9135
14495873d28db
1525237c69bbd
hex13a9c7c4681

1351245121153 has 2 divisors, whose sum is σ = 1351245121154. Its totient is φ = 1351245121152.

The previous prime is 1351245121151. The next prime is 1351245121169. The reversal of 1351245121153 is 3511215421531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1348959133809 + 2285987344 = 1161447^2 + 47812^2 .

It is an emirp because it is prime and its reverse (3511215421531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1351245121153 - 21 = 1351245121151 is a prime.

Together with 1351245121151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1351245121151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675622560576 + 675622560577.

It is an arithmetic number, because the mean of its divisors is an integer number (675622560577).

Almost surely, 21351245121153 is an apocalyptic number.

It is an amenable number.

1351245121153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351245121153 is an equidigital number, since it uses as much as digits as its factorization.

1351245121153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18000, while the sum is 34.

The spelling of 1351245121153 in words is "one trillion, three hundred fifty-one billion, two hundred forty-five million, one hundred twenty-one thousand, one hundred fifty-three".