Base | Representation |
---|---|
bin | 10000000110111… |
… | …11000101001111 |
3 | 100102021101112022 |
4 | 20003133011033 |
5 | 234043201341 |
6 | 21224200355 |
7 | 3230412206 |
oct | 1003370517 |
9 | 312241468 |
10 | 135131471 |
11 | 6a307302 |
12 | 393090bb |
13 | 21cc4367 |
14 | 13d3823d |
15 | bce3e4b |
hex | 80df14f |
135131471 has 2 divisors, whose sum is σ = 135131472. Its totient is φ = 135131470.
The previous prime is 135131467. The next prime is 135131473. The reversal of 135131471 is 174131531.
135131471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135131471 - 22 = 135131467 is a prime.
It is a super-3 number, since 3×1351314713 (a number of 25 digits) contains 333 as substring.
Together with 135131473, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 135131471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135131473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67565735 + 67565736.
It is an arithmetic number, because the mean of its divisors is an integer number (67565736).
Almost surely, 2135131471 is an apocalyptic number.
135131471 is a deficient number, since it is larger than the sum of its proper divisors (1).
135131471 is an equidigital number, since it uses as much as digits as its factorization.
135131471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1260, while the sum is 26.
The square root of 135131471 is about 11624.6062729023. The cubic root of 135131471 is about 513.1592575650.
The spelling of 135131471 in words is "one hundred thirty-five million, one hundred thirty-one thousand, four hundred seventy-one".
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