Base | Representation |
---|---|
bin | 111110111011100111… |
… | …0101010111111101001 |
3 | 110220211102212211101021 |
4 | 1331313032222333221 |
5 | 4203233421233001 |
6 | 142030123452441 |
7 | 12523000526524 |
oct | 1756716527751 |
9 | 426742784337 |
10 | 135144321001 |
11 | 5235049a698 |
12 | 22237687121 |
13 | c9898c4461 |
14 | 67807b7bbb |
15 | 37ae7c6ba1 |
hex | 1f773aafe9 |
135144321001 has 2 divisors, whose sum is σ = 135144321002. Its totient is φ = 135144321000.
The previous prime is 135144320999. The next prime is 135144321071. The reversal of 135144321001 is 100123441531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75942131776 + 59202189225 = 275576^2 + 243315^2 .
It is a cyclic number.
It is not a de Polignac number, because 135144321001 - 21 = 135144320999 is a prime.
Together with 135144320999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (135144321071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67572160500 + 67572160501.
It is an arithmetic number, because the mean of its divisors is an integer number (67572160501).
Almost surely, 2135144321001 is an apocalyptic number.
It is an amenable number.
135144321001 is a deficient number, since it is larger than the sum of its proper divisors (1).
135144321001 is an equidigital number, since it uses as much as digits as its factorization.
135144321001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 135144321001 its reverse (100123441531), we get a palindrome (235267762532).
The spelling of 135144321001 in words is "one hundred thirty-five billion, one hundred forty-four million, three hundred twenty-one thousand, one".
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