Base | Representation |
---|---|
bin | 10011101010101000111… |
… | …000110101101001101101 |
3 | 11210012100002121222200022 |
4 | 103222220320311221231 |
5 | 134120234004444203 |
6 | 2512503220211525 |
7 | 166432161454622 |
oct | 23525070655155 |
9 | 4705302558608 |
10 | 1351453203053 |
11 | 48116a1121a8 |
12 | 199b06b39ba5 |
13 | 9a597c52c15 |
14 | 495a6cba349 |
15 | 2524b16da38 |
hex | 13aa8e35a6d |
1351453203053 has 2 divisors, whose sum is σ = 1351453203054. Its totient is φ = 1351453203052.
The previous prime is 1351453203011. The next prime is 1351453203073. The reversal of 1351453203053 is 3503023541531.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1171098401929 + 180354801124 = 1082173^2 + 424682^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351453203053 - 232 = 1347158235757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351453203073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675726601526 + 675726601527.
It is an arithmetic number, because the mean of its divisors is an integer number (675726601527).
Almost surely, 21351453203053 is an apocalyptic number.
It is an amenable number.
1351453203053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351453203053 is an equidigital number, since it uses as much as digits as its factorization.
1351453203053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 35.
Adding to 1351453203053 its reverse (3503023541531), we get a palindrome (4854476744584).
The spelling of 1351453203053 in words is "one trillion, three hundred fifty-one billion, four hundred fifty-three million, two hundred three thousand, fifty-three".
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