1351453334141 has 2 divisors, whose sum is σ = 1351453334142. Its totient is φ = 1351453334140.

The previous prime is 1351453334111. The next prime is 1351453334197. The reversal of 1351453334141 is 1414333541531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 962270750116 + 389182584025 = 980954^2 + 623845^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351453334141 - 2²² = 1351449139837 is a prime.

It is a super-2 number, since 2×1351453334141² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1351453334095 and 1351453334104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351453334111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675726667070 + 675726667071.

It is an arithmetic number, because the mean of its divisors is an integer number (675726667071).

Almost surely, 2^{1351453334141} is an apocalyptic number.

It is an amenable number.

1351453334141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351453334141 is an equidigital number, since it uses as much as digits as its factorization.

1351453334141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 38.

Adding to 1351453334141 its reverse (1414333541531), we get a palindrome (2765786875672).

The spelling of 1351453334141 in words is "one trillion, three hundred fifty-one billion, four hundred fifty-three million, three hundred thirty-four thousand, one hundred forty-one".