Base | Representation |
---|---|
bin | 111110111011111000… |
… | …0001010011011111111 |
3 | 110220212001101212122111 |
4 | 1331313300022123333 |
5 | 4203243143204133 |
6 | 142031035554451 |
7 | 12523135254046 |
oct | 1756760123377 |
9 | 426761355574 |
10 | 135153100543 |
11 | 5235544690a |
12 | 2223a5bba27 |
13 | c98b679656 |
14 | 6781a2155d |
15 | 37b045d1cd |
hex | 1f77c0a6ff |
135153100543 has 2 divisors, whose sum is σ = 135153100544. Its totient is φ = 135153100542.
The previous prime is 135153100541. The next prime is 135153100571. The reversal of 135153100543 is 345001351531.
It is a weak prime.
It is an emirp because it is prime and its reverse (345001351531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135153100543 - 21 = 135153100541 is a prime.
Together with 135153100541, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135153100541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67576550271 + 67576550272.
It is an arithmetic number, because the mean of its divisors is an integer number (67576550272).
Almost surely, 2135153100543 is an apocalyptic number.
135153100543 is a deficient number, since it is larger than the sum of its proper divisors (1).
135153100543 is an equidigital number, since it uses as much as digits as its factorization.
135153100543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 135153100543 in words is "one hundred thirty-five billion, one hundred fifty-three million, one hundred thousand, five hundred forty-three".
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