Base | Representation |
---|---|
bin | 10011101010110100001… |
… | …011100001010001110101 |
3 | 11210012211022002212122102 |
4 | 103222310023201101311 |
5 | 134121131004242332 |
6 | 2512534104511445 |
7 | 166436651646353 |
oct | 23526413412165 |
9 | 4705738085572 |
10 | 1351642649717 |
11 | 481257047298 |
12 | 199b5a47b585 |
13 | 9a5c8283839 |
14 | 495c41127d3 |
15 | 2525cae1062 |
hex | 13ab42e1475 |
1351642649717 has 2 divisors, whose sum is σ = 1351642649718. Its totient is φ = 1351642649716.
The previous prime is 1351642649711. The next prime is 1351642649719. The reversal of 1351642649717 is 7179462461531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1121313684241 + 230328965476 = 1058921^2 + 479926^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351642649717 - 24 = 1351642649701 is a prime.
Together with 1351642649719, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351642649711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675821324858 + 675821324859.
It is an arithmetic number, because the mean of its divisors is an integer number (675821324859).
Almost surely, 21351642649717 is an apocalyptic number.
It is an amenable number.
1351642649717 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351642649717 is an equidigital number, since it uses as much as digits as its factorization.
1351642649717 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7620480, while the sum is 56.
The spelling of 1351642649717 in words is "one trillion, three hundred fifty-one billion, six hundred forty-two million, six hundred forty-nine thousand, seven hundred seventeen".
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