1352011301 has 2 divisors, whose sum is σ = 1352011302. Its totient is φ = 1352011300.

The previous prime is 1352011279. The next prime is 1352011303. The reversal of 1352011301 is 1031102531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1319578276 + 32433025 = 36326^2 + 5695^2 .

It is a cyclic number.

It is not a de Polignac number, because 1352011301 - 2¹⁰ = 1352010277 is a prime.

Together with 1352011303, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1352011301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1352011303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676005650 + 676005651.

It is an arithmetic number, because the mean of its divisors is an integer number (676005651).

Almost surely, 2^1352011301 is an apocalyptic number.

It is an amenable number.

1352011301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1352011301 is an equidigital number, since it uses as much as digits as its factorization.

1352011301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 1352011301 is about 36769.7062947204. The cubic root of 1352011301 is about 1105.7580436288.

Adding to 1352011301 its reverse (1031102531), we get a palindrome (2383113832).

The spelling of 1352011301 in words is "one billion, three hundred fifty-two million, eleven thousand, three hundred one".