Base | Representation |
---|---|
bin | 1100010010111111110011… |
… | …0010010111111111001111 |
3 | 1202212112210002222220010111 |
4 | 3010233330302113333033 |
5 | 3233004442301110044 |
6 | 44431122225220451 |
7 | 2563552446336166 |
oct | 304577462277717 |
9 | 52775702886114 |
10 | 13520503144399 |
11 | 4343016601029 |
12 | 1624445191727 |
13 | 770c937c71a4 |
14 | 34a5782a43dd |
15 | 186a752c0b34 |
hex | c4bfcc97fcf |
13520503144399 has 2 divisors, whose sum is σ = 13520503144400. Its totient is φ = 13520503144398.
The previous prime is 13520503144387. The next prime is 13520503144433. The reversal of 13520503144399 is 99344130502531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13520503144399 - 225 = 13520469589967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13520503144319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760251572199 + 6760251572200.
It is an arithmetic number, because the mean of its divisors is an integer number (6760251572200).
Almost surely, 213520503144399 is an apocalyptic number.
13520503144399 is a deficient number, since it is larger than the sum of its proper divisors (1).
13520503144399 is an equidigital number, since it uses as much as digits as its factorization.
13520503144399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1749600, while the sum is 49.
The spelling of 13520503144399 in words is "thirteen trillion, five hundred twenty billion, five hundred three million, one hundred forty-four thousand, three hundred ninety-nine".
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